Solve for t 5(4+t)=5t+20

$5 (4 + t) = 5 t + 20$

Simplify $5 (4 + t)$ .

Rewrite.

$0 + 0 + 5 (4 + t) = 5 t + 20$

Simplify by adding zeros.

$5 (4 + t) = 5 t + 20$

Apply the distributive property.

$5 \cdot 4 + 5 t = 5 t + 20$

Multiply $5$ by $4$ .

$20 + 5 t = 5 t + 20$

Move all terms containing $t$ to the left side of the equation.

Subtract $5 t$ from both sides of the equation.

$20 + 5 t - 5 t = 20$

Combine the opposite terms in $20 + 5 t - 5 t$ .

Subtract $5 t$ from $5 t$ .

$20 + 0 = 20$

Add $20$ and $0$ .

$20 = 20$

Since $20 = 20$ , the equation will always be true for any value of $t$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$