Solve for t 7=3/5t-2

$7 = \frac{3}{5} t - 2$

Rewrite the equation as $\frac{3}{5} t - 2 = 7$ .

$\frac{3}{5} t - 2 = 7$

Combine $\frac{3}{5}$ and $t$ .

$\frac{3 t}{5} - 2 = 7$

Move all terms not containing $t$ to the right side of the equation.

Add $2$ to both sides of the equation.

$\frac{3 t}{5} = 7 + 2$

Add $7$ and $2$ .

$\frac{3 t}{5} = 9$

Multiply both sides of the equation by $\frac{5}{3}$ .

$\frac{5}{3} \cdot \frac{3 t}{5} = \frac{5}{3} \cdot 9$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{5}{3} \cdot \frac{3 t}{5}$ .

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5}{3} \cdot \frac{3 t}{5} = \frac{5}{3} \cdot 9$

Rewrite the expression.

$\frac{1}{3} (3 t) = \frac{5}{3} \cdot 9$

Cancel the common factor of $3$ .

Factor $3$ out of $3 t$ .

$\frac{1}{3} (3 (t)) = \frac{5}{3} \cdot 9$

Cancel the common factor.

$\frac{1}{3} (3 t) = \frac{5}{3} \cdot 9$

Rewrite the expression.

$t = \frac{5}{3} \cdot 9$

Simplify the right side.

Simplify $\frac{5}{3} \cdot 9$ .

Cancel the common factor of $3$ .

Factor $3$ out of $9$ .

$t = \frac{5}{3} \cdot (3 (3))$

Cancel the common factor.

$t = \frac{5}{3} \cdot (3 \cdot 3)$

Rewrite the expression.

$t = 5 \cdot 3$

Multiply $5$ by $3$ .

$t = 15$