Solve for t 8x^2-4tx+3=0

$8 x^{2} - 4 t x + 3 = 0$

Step 1

Move all terms not containing $t$ to the right side of the equation.

Subtract $8 x^{2}$ from both sides of the equation.

$- 4 t x + 3 = - 8 x^{2}$

Subtract $3$ from both sides of the equation.

$- 4 t x = - 8 x^{2} - 3$

Step 2

Divide each term in $- 4 t x = - 8 x^{2} - 3$ by $- 4 x$ and simplify.

Divide each term in $- 4 t x = - 8 x^{2} - 3$ by $- 4 x$ .

$\frac{- 4 t x}{- 4 x} = \frac{- 8 x^{2}}{- 4 x} + \frac{- 3}{- 4 x}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 t x}{- 4 x} = \frac{- 8 x^{2}}{- 4 x} + \frac{- 3}{- 4 x}$

Rewrite the expression.

$\frac{t x}{x} = \frac{- 8 x^{2}}{- 4 x} + \frac{- 3}{- 4 x}$

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{t x}{x} = \frac{- 8 x^{2}}{- 4 x} + \frac{- 3}{- 4 x}$

Divide $t$ by $1$ .

$t = \frac{- 8 x^{2}}{- 4 x} + \frac{- 3}{- 4 x}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 8$ and $- 4$ .

Factor $- 4$ out of $- 8 x^{2}$ .

$t = \frac{- 4 (2 x^{2})}{- 4 x} + \frac{- 3}{- 4 x}$

Cancel the common factors.

Factor $- 4$ out of $- 4 x$ .

$t = \frac{- 4 (2 x^{2})}{- 4 (x)} + \frac{- 3}{- 4 x}$

Cancel the common factor.

$t = \frac{- 4 (2 x^{2})}{- 4 x} + \frac{- 3}{- 4 x}$

Rewrite the expression.

$t = \frac{2 x^{2}}{x} + \frac{- 3}{- 4 x}$

Cancel the common factor of $x^{2}$ and $x$ .

Factor $x$ out of $2 x^{2}$ .

$t = \frac{x (2 x)}{x} + \frac{- 3}{- 4 x}$

Cancel the common factors.

Raise $x$ to the power of $1$ .

$t = \frac{x (2 x)}{x^{1}} + \frac{- 3}{- 4 x}$

Factor $x$ out of $x^{1}$ .

$t = \frac{x (2 x)}{x \cdot 1} + \frac{- 3}{- 4 x}$

Cancel the common factor.

$t = \frac{x (2 x)}{x \cdot 1} + \frac{- 3}{- 4 x}$

Rewrite the expression.

$t = \frac{2 x}{1} + \frac{- 3}{- 4 x}$

Divide $2 x$ by $1$ .

$t = 2 x + \frac{- 3}{- 4 x}$

Dividing two negative values results in a positive value.

$t = 2 x + \frac{3}{4 x}$

Solve for t 8x^2-4tx+3=0

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