Solve for t A=p(1+rt)

$A = p (1 + r t)$

Step 1

Rewrite the equation as $p (1 + r t) = A$ .

$p (1 + r t) = A$

Step 2

Divide each term in $p (1 + r t) = A$ by $p$ and simplify.

Divide each term in $p (1 + r t) = A$ by $p$ .

$\frac{p (1 + r t)}{p} = \frac{A}{p}$

Simplify the left side.

Cancel the common factor of $p$ .

Cancel the common factor.

$\frac{p (1 + r t)}{p} = \frac{A}{p}$

Divide $1 + r t$ by $1$ .

$1 + r t = \frac{A}{p}$

Step 3

Subtract $1$ from both sides of the equation.

$r t = \frac{A}{p} - 1$

Step 4

Divide each term in $r t = \frac{A}{p} - 1$ by $r$ and simplify.

Divide each term in $r t = \frac{A}{p} - 1$ by $r$ .

$\frac{r t}{r} = \frac{\frac{A}{p}}{r} + \frac{- 1}{r}$

Simplify the left side.

Cancel the common factor of $r$ .

Cancel the common factor.

$\frac{r t}{r} = \frac{\frac{A}{p}}{r} + \frac{- 1}{r}$

Divide $t$ by $1$ .

$t = \frac{\frac{A}{p}}{r} + \frac{- 1}{r}$

Simplify the right side.

Simplify each term.

Multiply the numerator by the reciprocal of the denominator.

$t = \frac{A}{p} \cdot \frac{1}{r} + \frac{- 1}{r}$

Multiply $\frac{A}{p}$ by $\frac{1}{r}$ .

$t = \frac{A}{p r} + \frac{- 1}{r}$

Move the negative in front of the fraction.

$t = \frac{A}{p r} - \frac{1}{r}$