Solve for t f(t)=2t-3

$f (t) = 2 t - 3$

Step 1

Subtract $2 t$ from both sides of the equation.

$f t - 2 t = - 3$

Step 2

Factor $t$ out of $f t - 2 t$ .

Factor $t$ out of $f t$ .

$t f - 2 t = - 3$

Factor $t$ out of $- 2 t$ .

$t f + t \cdot - 2 = - 3$

Factor $t$ out of $t f + t \cdot - 2$ .

$t (f - 2) = - 3$

Step 3

Divide each term in $t (f - 2) = - 3$ by $f - 2$ and simplify.

Divide each term in $t (f - 2) = - 3$ by $f - 2$ .

$\frac{t (f - 2)}{f - 2} = \frac{- 3}{f - 2}$

Simplify the left side.

Cancel the common factor of $f - 2$ .

Cancel the common factor.

$\frac{t (f - 2)}{f - 2} = \frac{- 3}{f - 2}$

Divide $t$ by $1$ .

$t = \frac{- 3}{f - 2}$

Simplify the right side.

Move the negative in front of the fraction.

$t = - \frac{3}{f - 2}$