Solve for t h=80t-16t^2

$h = 80 t - 16 t^{2}$

Step 1

Rewrite the equation as $80 t - 16 t^{2} = h$ .

$80 t - 16 t^{2} = h$

Step 2

Subtract $h$ from both sides of the equation.

$80 t - 16 t^{2} - h = 0$

Step 3

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 4

Substitute the values $a = - 16$ , $b = 80$ , and $c = - h$ into the quadratic formula and solve for $t$ .

$\frac{- 80 \pm \sqrt{80^{2} - 4 \cdot (- 16 \cdot (- h))}}{2 \cdot - 16}$

Step 5

Simplify.

Simplify the numerator.

Raise $80$ to the power of $2$ .

$t = \frac{- 80 \pm \sqrt{6400 - 4 \cdot - 16 \cdot (- 1 h)}}{2 \cdot - 16}$

Multiply $- 4 \cdot - 16 \cdot - 1$ .

Multiply $- 4$ by $- 16$ .

$t = \frac{- 80 \pm \sqrt{6400 + 64 \cdot (- 1 h)}}{2 \cdot - 16}$

Multiply $64$ by $- 1$ .

$t = \frac{- 80 \pm \sqrt{6400 - 64 h}}{2 \cdot - 16}$

Factor $64$ out of $6400 - 64 h$ .

Factor $64$ out of $6400$ .

$t = \frac{- 80 \pm \sqrt{64 (100) - 64 h}}{2 \cdot - 16}$

Factor $64$ out of $- 64 h$ .

$t = \frac{- 80 \pm \sqrt{64 (100) + 64 (- h)}}{2 \cdot - 16}$

Factor $64$ out of $64 (100) + 64 (- h)$ .

$t = \frac{- 80 \pm \sqrt{64 (100 - h)}}{2 \cdot - 16}$

Rewrite $64 (100 - h)$ as $8^{2} (10^{2} - h)$ .

Rewrite $64$ as $8^{2}$ .

$t = \frac{- 80 \pm \sqrt{8^{2} (100 - h)}}{2 \cdot - 16}$

Rewrite $100$ as $10^{2}$ .

$t = \frac{- 80 \pm \sqrt{8^{2} (10^{2} - h)}}{2 \cdot - 16}$

Pull terms out from under the radical.

$t = \frac{- 80 \pm 8 \sqrt{10^{2} - h}}{2 \cdot - 16}$

Raise $10$ to the power of $2$ .

$t = \frac{- 80 \pm 8 \sqrt{100 - h}}{2 \cdot - 16}$

Multiply $2$ by $- 16$ .

$t = \frac{- 80 \pm 8 \sqrt{100 - h}}{- 32}$

Simplify $\frac{- 80 \pm 8 \sqrt{100 - h}}{- 32}$ .

$t = \frac{10 \pm \sqrt{100 - h}}{4}$

Step 6

The final answer is the combination of both solutions.

$t = \frac{10 + \sqrt{100 - h}}{4}$

$t = \frac{10 - \sqrt{100 - h}}{4}$

Solve for t h=80t-16t^2

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