Solve for t k(t)=13t-2

$k (t) = 13 t - 2$

Subtract $13 t$ from both sides of the equation.

$k t - 13 t = - 2$

Factor $t$ out of $k t - 13 t$ .

Factor $t$ out of $k t$ .

$t k - 13 t = - 2$

Factor $t$ out of $- 13 t$ .

$t k + t \cdot - 13 = - 2$

Factor $t$ out of $t k + t \cdot - 13$ .

$t (k - 13) = - 2$

Divide each term in $t (k - 13) = - 2$ by $k - 13$ and simplify.

Divide each term in $t (k - 13) = - 2$ by $k - 13$ .

$\frac{t (k - 13)}{k - 13} = \frac{- 2}{k - 13}$

Simplify the left side.

Cancel the common factor of $k - 13$ .

Cancel the common factor.

$\frac{t (k - 13)}{k - 13} = \frac{- 2}{k - 13}$

Divide $t$ by $1$ .

$t = \frac{- 2}{k - 13}$

Simplify the right side.

Move the negative in front of the fraction.

$t = - \frac{2}{k - 13}$