Solve for t (t+2)^2=7

${(t + 2)}^{2} = 7$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$t + 2 = \pm \sqrt{7}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$t + 2 = \sqrt{7}$

Subtract $2$ from both sides of the equation.

$t = \sqrt{7} - 2$

Next, use the negative value of the $\pm$ to find the second solution.

$t + 2 = - \sqrt{7}$

Subtract $2$ from both sides of the equation.

$t = - \sqrt{7} - 2$

The complete solution is the result of both the positive and negative portions of the solution.

$t = \sqrt{7} - 2, - \sqrt{7} - 2$

The result can be shown in multiple forms.

Exact Form:

$t = \sqrt{7} - 2, - \sqrt{7} - 2$

Decimal Form:

$t = 0.64575131 \dots, - 4.64575131 \dots$