Solve for t -(t+2)=-3t+23

$- (t + 2) = - 3 t + 23$

Simplify $- (t + 2)$ .

Rewrite.

$0 + 0 - (t + 2) = - 3 t + 23$

Simplify by adding zeros.

$- (t + 2) = - 3 t + 23$

Apply the distributive property.

$- t - 1 \cdot 2 = - 3 t + 23$

Multiply $- 1$ by $2$ .

$- t - 2 = - 3 t + 23$

Move all terms containing $t$ to the left side of the equation.

Add $3 t$ to both sides of the equation.

$- t - 2 + 3 t = 23$

Add $- t$ and $3 t$ .

$2 t - 2 = 23$

Move all terms not containing $t$ to the right side of the equation.

Add $2$ to both sides of the equation.

$2 t = 23 + 2$

Add $23$ and $2$ .

$2 t = 25$

Divide each term in $2 t = 25$ by $2$ and simplify.

Divide each term in $2 t = 25$ by $2$ .

$\frac{2 t}{2} = \frac{25}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 t}{2} = \frac{25}{2}$

Divide $t$ by $1$ .

$t = \frac{25}{2}$

The result can be shown in multiple forms.

Exact Form:

$t = \frac{25}{2}$

Decimal Form:

$t = 12.5$

Mixed Number Form:

$t = 12 \frac{1}{2}$