Solve for t t-27=-(27-t)

$t - 27 = - (27 - t)$

Simplify $- (27 - t)$ .

Rewrite.

$t - 27 = 0 + 0 - (27 - t)$

Simplify by adding zeros.

$t - 27 = - (27 - t)$

Apply the distributive property.

$t - 27 = - 1 \cdot 27 - - t$

Multiply $- 1$ by $27$ .

$t - 27 = - 27 - - t$

Multiply $- - t$ .

Multiply $- 1$ by $- 1$ .

$t - 27 = - 27 + 1 t$

Multiply $t$ by $1$ .

$t - 27 = - 27 + t$

Move all terms containing $t$ to the left side of the equation.

Subtract $t$ from both sides of the equation.

$t - 27 - t = - 27$

Combine the opposite terms in $t - 27 - t$ .

Subtract $t$ from $t$ .

$0 - 27 = - 27$

Subtract $27$ from $0$ .

$- 27 = - 27$

Since $- 27 = - 27$ , the equation will always be true for any value of $t$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$