Solve for t t=2pi square root of l/9.8

$t = 2 π \sqrt{\frac{l}{9.8}}$

Step 1

Multiply by $1$ .

$t = 2 π \sqrt{\frac{1 l}{9.8}}$

Step 2

Factor $9.8$ out of $9.8$ .

$t = 2 π \sqrt{\frac{1 l}{9.8 (1)}}$

Step 3

Separate fractions.

$t = 2 π \sqrt{\frac{1}{9.8} \cdot \frac{l}{1}}$

Step 4

Divide $1$ by $9.8$ .

$t = 2 π \sqrt{0.10204081 \frac{l}{1}}$

Step 5

Divide $l$ by $1$ .

$t = 2 π \sqrt{0.10204081 l}$

Step 6

Rewrite $0.10204081 l$ as ${({0.56518871}^{2})}^{2} l$ .

Rewrite $0.10204081$ as ${0.31943828}^{2}$ .

$t = 2 π \sqrt{{0.31943828}^{2} l}$

Rewrite $0.31943828$ as ${0.56518871}^{2}$ .

$t = 2 π \sqrt{{({0.56518871}^{2})}^{2} l}$

Step 7

Pull terms out from under the radical.

$t = 2 π ({0.56518871}^{2} \sqrt{l})$

Step 8

Raise $0.56518871$ to the power of $2$ .

$t = 2 π (0.31943828 \sqrt{l})$

Step 9

Multiply $2 π (0.31943828 \sqrt{l})$ .

Multiply $0.31943828$ by $2$ .

$t = 0.63887656 π \sqrt{l}$

Multiply $0.63887656$ by $π$ .

$t = 2.00708992 \sqrt{l}$