Solve for t -t-4(2t-5)=20

$- t - 4 (2 t - 5) = 20$

Step 1

Simplify $- t - 4 (2 t - 5)$ .

Simplify each term.

Apply the distributive property.

$- t - 4 (2 t) - 4 \cdot - 5 = 20$

Multiply $2$ by $- 4$ .

$- t - 8 t - 4 \cdot - 5 = 20$

Multiply $- 4$ by $- 5$ .

$- t - 8 t + 20 = 20$

Subtract $8 t$ from $- t$ .

$- 9 t + 20 = 20$

Step 2

Move all terms not containing $t$ to the right side of the equation.

Subtract $20$ from both sides of the equation.

$- 9 t = 20 - 20$

Subtract $20$ from $20$ .

$- 9 t = 0$

Step 3

Divide each term in $- 9 t = 0$ by $- 9$ and simplify.

Divide each term in $- 9 t = 0$ by $- 9$ .

$\frac{- 9 t}{- 9} = \frac{0}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 t}{- 9} = \frac{0}{- 9}$

Divide $t$ by $1$ .

$t = \frac{0}{- 9}$

Simplify the right side.

Divide $0$ by $- 9$ .

$t = 0$