Solve for t (t+-a)(t+-b)=0

$(t + - a) (t + - b) = 0$

Replace all occurrences of $+$ $-$ with a single $-$ . A plus sign followed by a minus sign has the same mathematical meaning as a single minus sign because $1 \cdot - 1 = - 1$

$(t - a) (t - b) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$t - a = 0$

$t - b = 0$

Set $t - a$ equal to $0$ and solve for $t$ .

Set $t - a$ equal to $0$ .

$t - a = 0$

Add $a$ to both sides of the equation.

$t = a$

Set $t - b$ equal to $0$ and solve for $t$ .

Set $t - b$ equal to $0$ .

$t - b = 0$

Add $b$ to both sides of the equation.

$t = b$

The final solution is all the values that make $(t - a) (t - b) = 0$ true.

$t = a$

$t = b$

Solve for t (t+-a)(t+-b)=0

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