Solve for t u=(3t)/4+2

$u = \frac{3 t}{4} + 2$

Rewrite the equation as $\frac{3 t}{4} + 2 = u$ .

$\frac{3 t}{4} + 2 = u$

Subtract $2$ from both sides of the equation.

$\frac{3 t}{4} = u - 2$

Multiply both sides of the equation by $\frac{4}{3}$ .

$\frac{4}{3} \cdot \frac{3 t}{4} = \frac{4}{3} (u - 2)$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{3} \cdot \frac{3 t}{4}$ .

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4}{3} \cdot \frac{3 t}{4} = \frac{4}{3} (u - 2)$

Rewrite the expression.

$\frac{1}{3} (3 t) = \frac{4}{3} (u - 2)$

Cancel the common factor of $3$ .

Factor $3$ out of $3 t$ .

$\frac{1}{3} (3 (t)) = \frac{4}{3} (u - 2)$

Cancel the common factor.

$\frac{1}{3} (3 t) = \frac{4}{3} (u - 2)$

Rewrite the expression.

$t = \frac{4}{3} (u - 2)$

Simplify the right side.

Simplify $\frac{4}{3} (u - 2)$ .

Apply the distributive property.

$t = \frac{4}{3} u + \frac{4}{3} \cdot - 2$

Combine $\frac{4}{3}$ and $u$ .

$t = \frac{4 u}{3} + \frac{4}{3} \cdot - 2$

Multiply $\frac{4}{3} \cdot - 2$ .

Combine $\frac{4}{3}$ and $- 2$ .

$t = \frac{4 u}{3} + \frac{4 \cdot - 2}{3}$

Multiply $4$ by $- 2$ .

$t = \frac{4 u}{3} + \frac{- 8}{3}$

Move the negative in front of the fraction.

$t = \frac{4 u}{3} - \frac{8}{3}$