Solve for u 2(3u+7)=-4(3-2u)

$2 (3 u + 7) = - 4 (3 - 2 u)$

Step 1

Simplify $2 (3 u + 7)$ .

Rewrite.

$0 + 0 + 2 (3 u + 7) = - 4 (3 - 2 u)$

Simplify by adding zeros.

$2 (3 u + 7) = - 4 (3 - 2 u)$

Apply the distributive property.

$2 (3 u) + 2 \cdot 7 = - 4 (3 - 2 u)$

Multiply.

Multiply $3$ by $2$ .

$6 u + 2 \cdot 7 = - 4 (3 - 2 u)$

Multiply $2$ by $7$ .

$6 u + 14 = - 4 (3 - 2 u)$

Step 2

Simplify $- 4 (3 - 2 u)$ .

Apply the distributive property.

$6 u + 14 = - 4 \cdot 3 - 4 (- 2 u)$

Multiply.

Multiply $- 4$ by $3$ .

$6 u + 14 = - 12 - 4 (- 2 u)$

Multiply $- 2$ by $- 4$ .

$6 u + 14 = - 12 + 8 u$

Step 3

Move all terms containing $u$ to the left side of the equation.

Subtract $8 u$ from both sides of the equation.

$6 u + 14 - 8 u = - 12$

Subtract $8 u$ from $6 u$ .

$- 2 u + 14 = - 12$

Step 4

Move all terms not containing $u$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$- 2 u = - 12 - 14$

Subtract $14$ from $- 12$ .

$- 2 u = - 26$

Step 5

Divide each term in $- 2 u = - 26$ by $- 2$ and simplify.

Divide each term in $- 2 u = - 26$ by $- 2$ .

$\frac{- 2 u}{- 2} = \frac{- 26}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 u}{- 2} = \frac{- 26}{- 2}$

Divide $u$ by $1$ .

$u = \frac{- 26}{- 2}$

Simplify the right side.

Divide $- 26$ by $- 2$ .

$u = 13$

Solve for u 2(3u+7)=-4(3-2u)

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