Solve for u 2(u+1)+4u=3(2u-1)+8

$2 (u + 1) + 4 u = 3 (2 u - 1) + 8$

Simplify $2 (u + 1) + 4 u$ .

Simplify each term.

Apply the distributive property.

$2 u + 2 \cdot 1 + 4 u = 3 (2 u - 1) + 8$

Multiply $2$ by $1$ .

$2 u + 2 + 4 u = 3 (2 u - 1) + 8$

Add $2 u$ and $4 u$ .

$6 u + 2 = 3 (2 u - 1) + 8$

Simplify $3 (2 u - 1) + 8$ .

Simplify each term.

Apply the distributive property.

$6 u + 2 = 3 (2 u) + 3 \cdot - 1 + 8$

Multiply $2$ by $3$ .

$6 u + 2 = 6 u + 3 \cdot - 1 + 8$

Multiply $3$ by $- 1$ .

$6 u + 2 = 6 u - 3 + 8$

Add $- 3$ and $8$ .

$6 u + 2 = 6 u + 5$

Move all terms containing $u$ to the left side of the equation.

Subtract $6 u$ from both sides of the equation.

$6 u + 2 - 6 u = 5$

Combine the opposite terms in $6 u + 2 - 6 u$ .

Subtract $6 u$ from $6 u$ .

$0 + 2 = 5$

Add $0$ and $2$ .

$2 = 5$

Since $2 \neq 5$ , there are no solutions.

No solution