Solve for u 3(2u+5)=33

$3 (2 u + 5) = 33$

Step 1

Divide each term in $3 (2 u + 5) = 33$ by $3$ and simplify.

Divide each term in $3 (2 u + 5) = 33$ by $3$ .

$\frac{3 (2 u + 5)}{3} = \frac{33}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (2 u + 5)}{3} = \frac{33}{3}$

Divide $2 u + 5$ by $1$ .

$2 u + 5 = \frac{33}{3}$

Simplify the right side.

Divide $33$ by $3$ .

$2 u + 5 = 11$

Step 2

Move all terms not containing $u$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$2 u = 11 - 5$

Subtract $5$ from $11$ .

$2 u = 6$

Step 3

Divide each term in $2 u = 6$ by $2$ and simplify.

Divide each term in $2 u = 6$ by $2$ .

$\frac{2 u}{2} = \frac{6}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 u}{2} = \frac{6}{2}$

Divide $u$ by $1$ .

$u = \frac{6}{2}$

Simplify the right side.

Divide $6$ by $2$ .

$u = 3$