Solve for u 3(u+2)+4=5(u-1)+u

$3 (u + 2) + 4 = 5 (u - 1) + u$

Since $u$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$5 (u - 1) + u = 3 (u + 2) + 4$

Simplify $5 (u - 1) + u$ .

Simplify each term.

Apply the distributive property.

$5 u + 5 \cdot - 1 + u = 3 (u + 2) + 4$

Multiply $5$ by $- 1$ .

$5 u - 5 + u = 3 (u + 2) + 4$

Add $5 u$ and $u$ .

$6 u - 5 = 3 (u + 2) + 4$

Simplify $3 (u + 2) + 4$ .

Simplify each term.

Apply the distributive property.

$6 u - 5 = 3 u + 3 \cdot 2 + 4$

Multiply $3$ by $2$ .

$6 u - 5 = 3 u + 6 + 4$

Add $6$ and $4$ .

$6 u - 5 = 3 u + 10$

Move all terms containing $u$ to the left side of the equation.

Subtract $3 u$ from both sides of the equation.

$6 u - 5 - 3 u = 10$

Subtract $3 u$ from $6 u$ .

$3 u - 5 = 10$

Move all terms not containing $u$ to the right side of the equation.

Add $5$ to both sides of the equation.

$3 u = 10 + 5$

Add $10$ and $5$ .

$3 u = 15$

Divide each term in $3 u = 15$ by $3$ and simplify.

Divide each term in $3 u = 15$ by $3$ .

$\frac{3 u}{3} = \frac{15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 u}{3} = \frac{15}{3}$

Divide $u$ by $1$ .

$u = \frac{15}{3}$

Simplify the right side.

Divide $15$ by $3$ .

$u = 5$