Solve for u -4(u+1)+6u=2(u+2)-8

$- 4 (u + 1) + 6 u = 2 (u + 2) - 8$

Simplify $- 4 (u + 1) + 6 u$ .

Simplify each term.

Apply the distributive property.

$- 4 u - 4 \cdot 1 + 6 u = 2 (u + 2) - 8$

Multiply $- 4$ by $1$ .

$- 4 u - 4 + 6 u = 2 (u + 2) - 8$

Add $- 4 u$ and $6 u$ .

$2 u - 4 = 2 (u + 2) - 8$

Simplify $2 (u + 2) - 8$ .

Simplify each term.

Apply the distributive property.

$2 u - 4 = 2 u + 2 \cdot 2 - 8$

Multiply $2$ by $2$ .

$2 u - 4 = 2 u + 4 - 8$

Subtract $8$ from $4$ .

$2 u - 4 = 2 u - 4$

Move all terms containing $u$ to the left side of the equation.

Subtract $2 u$ from both sides of the equation.

$2 u - 4 - 2 u = - 4$

Combine the opposite terms in $2 u - 4 - 2 u$ .

Subtract $2 u$ from $2 u$ .

$0 - 4 = - 4$

Subtract $4$ from $0$ .

$- 4 = - 4$

Since $- 4 = - 4$ , the equation will always be true for any value of $u$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$