Solve for u -6(u+1)+8u=2(u-3)

$- 6 (u + 1) + 8 u = 2 (u - 3)$

Simplify $- 6 (u + 1) + 8 u$ .

Simplify each term.

Apply the distributive property.

$- 6 u - 6 \cdot 1 + 8 u = 2 (u - 3)$

Multiply $- 6$ by $1$ .

$- 6 u - 6 + 8 u = 2 (u - 3)$

Add $- 6 u$ and $8 u$ .

$2 u - 6 = 2 (u - 3)$

Simplify $2 (u - 3)$ .

Apply the distributive property.

$2 u - 6 = 2 u + 2 \cdot - 3$

Multiply $2$ by $- 3$ .

$2 u - 6 = 2 u - 6$

Move all terms containing $u$ to the left side of the equation.

Subtract $2 u$ from both sides of the equation.

$2 u - 6 - 2 u = - 6$

Combine the opposite terms in $2 u - 6 - 2 u$ .

Subtract $2 u$ from $2 u$ .

$0 - 6 = - 6$

Subtract $6$ from $0$ .

$- 6 = - 6$

Since $- 6 = - 6$ , the equation will always be true for any value of $u$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$