Solve for u -7-2u+7=3(-u-10)+4u

$- 7 - 2 u + 7 = 3 (- u - 10) + 4 u$

Since $u$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$3 (- u - 10) + 4 u = - 7 - 2 u + 7$

Simplify $3 (- u - 10) + 4 u$ .

Simplify each term.

Apply the distributive property.

$3 (- u) + 3 \cdot - 10 + 4 u = - 7 - 2 u + 7$

Multiply $- 1$ by $3$ .

$- 3 u + 3 \cdot - 10 + 4 u = - 7 - 2 u + 7$

Multiply $3$ by $- 10$ .

$- 3 u - 30 + 4 u = - 7 - 2 u + 7$

Add $- 3 u$ and $4 u$ .

$u - 30 = - 7 - 2 u + 7$

Combine the opposite terms in $- 7 - 2 u + 7$ .

Add $- 7$ and $7$ .

$u - 30 = - 2 u + 0$

Add $- 2 u$ and $0$ .

$u - 30 = - 2 u$

Move all terms containing $u$ to the left side of the equation.

Add $2 u$ to both sides of the equation.

$u - 30 + 2 u = 0$

Add $u$ and $2 u$ .

$3 u - 30 = 0$

Add $30$ to both sides of the equation.

$3 u = 30$

Divide each term in $3 u = 30$ by $3$ and simplify.

Divide each term in $3 u = 30$ by $3$ .

$\frac{3 u}{3} = \frac{30}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 u}{3} = \frac{30}{3}$

Divide $u$ by $1$ .

$u = \frac{30}{3}$

Simplify the right side.

Divide $30$ by $3$ .

$u = 10$