Solve for u u^2-2u-8=0

$u^{2} - 2 u - 8 = 0$

Factor $u^{2} - 2 u - 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 8$ and whose sum is $- 2$ .

$- 4, 2$

Write the factored form using these integers.

$(u - 4) (u + 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$u - 4 = 0$

$u + 2 = 0$

Set $u - 4$ equal to $0$ and solve for $u$ .

Set $u - 4$ equal to $0$ .

$u - 4 = 0$

Add $4$ to both sides of the equation.

$u = 4$

Set $u + 2$ equal to $0$ and solve for $u$ .

Set $u + 2$ equal to $0$ .

$u + 2 = 0$

Subtract $2$ from both sides of the equation.

$u = - 2$

The final solution is all the values that make $(u - 4) (u + 2) = 0$ true.

$u = 4, - 2$

Solve for u u^2-2u-8=0

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