Solve for u u^2+7u+6=0

$u^{2} + 7 u + 6 = 0$

Step 1

Factor $u^{2} + 7 u + 6$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $6$ and whose sum is $7$ .

$1, 6$

Write the factored form using these integers.

$(u + 1) (u + 6) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$u + 1 = 0$

$u + 6 = 0$

Step 3

Set $u + 1$ equal to $0$ and solve for $u$ .

Set $u + 1$ equal to $0$ .

$u + 1 = 0$

Subtract $1$ from both sides of the equation.

$u = - 1$

Step 4

Set $u + 6$ equal to $0$ and solve for $u$ .

Set $u + 6$ equal to $0$ .

$u + 6 = 0$

Subtract $6$ from both sides of the equation.

$u = - 6$

Step 5

The final solution is all the values that make $(u + 1) (u + 6) = 0$ true.

$u = - 1, - 6$

Solve for u u^2+7u+6=0

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