Solve for v 2(3v-5)=2(v-11)-4

$2 (3 v - 5) = 2 (v - 11) - 4$

Simplify $2 (3 v - 5)$ .

Rewrite.

$0 + 0 + 2 (3 v - 5) = 2 (v - 11) - 4$

Simplify by adding zeros.

$2 (3 v - 5) = 2 (v - 11) - 4$

Apply the distributive property.

$2 (3 v) + 2 \cdot - 5 = 2 (v - 11) - 4$

Multiply.

Multiply $3$ by $2$ .

$6 v + 2 \cdot - 5 = 2 (v - 11) - 4$

Multiply $2$ by $- 5$ .

$6 v - 10 = 2 (v - 11) - 4$

Simplify $2 (v - 11) - 4$ .

Simplify each term.

Apply the distributive property.

$6 v - 10 = 2 v + 2 \cdot - 11 - 4$

Multiply $2$ by $- 11$ .

$6 v - 10 = 2 v - 22 - 4$

Subtract $4$ from $- 22$ .

$6 v - 10 = 2 v - 26$

Move all terms containing $v$ to the left side of the equation.

Subtract $2 v$ from both sides of the equation.

$6 v - 10 - 2 v = - 26$

Subtract $2 v$ from $6 v$ .

$4 v - 10 = - 26$

Move all terms not containing $v$ to the right side of the equation.

Add $10$ to both sides of the equation.

$4 v = - 26 + 10$

Add $- 26$ and $10$ .

$4 v = - 16$

Divide each term in $4 v = - 16$ by $4$ and simplify.

Divide each term in $4 v = - 16$ by $4$ .

$\frac{4 v}{4} = \frac{- 16}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 v}{4} = \frac{- 16}{4}$

Divide $v$ by $1$ .

$v = \frac{- 16}{4}$

Simplify the right side.

Divide $- 16$ by $4$ .

$v = - 4$