Solve for v 3(v+2)-v=2(v-1)+5

$3 (v + 2) - v = 2 (v - 1) + 5$

Step 1

Simplify $3 (v + 2) - v$ .

Simplify each term.

Apply the distributive property.

$3 v + 3 \cdot 2 - v = 2 (v - 1) + 5$

Multiply $3$ by $2$ .

$3 v + 6 - v = 2 (v - 1) + 5$

Subtract $v$ from $3 v$ .

$2 v + 6 = 2 (v - 1) + 5$

Step 2

Simplify $2 (v - 1) + 5$ .

Simplify each term.

Apply the distributive property.

$2 v + 6 = 2 v + 2 \cdot - 1 + 5$

Multiply $2$ by $- 1$ .

$2 v + 6 = 2 v - 2 + 5$

Add $- 2$ and $5$ .

$2 v + 6 = 2 v + 3$

Step 3

Move all terms containing $v$ to the left side of the equation.

Subtract $2 v$ from both sides of the equation.

$2 v + 6 - 2 v = 3$

Combine the opposite terms in $2 v + 6 - 2 v$ .

Subtract $2 v$ from $2 v$ .

$0 + 6 = 3$

Add $0$ and $6$ .

$6 = 3$

Step 4

Since $6 \neq 3$ , there are no solutions.

No solution