Solve for v 3(v+2)+v=4(v-1)+9

$3 (v + 2) + v = 4 (v - 1) + 9$

Step 1

Simplify $3 (v + 2) + v$ .

Simplify each term.

Apply the distributive property.

$3 v + 3 \cdot 2 + v = 4 (v - 1) + 9$

Multiply $3$ by $2$ .

$3 v + 6 + v = 4 (v - 1) + 9$

Add $3 v$ and $v$ .

$4 v + 6 = 4 (v - 1) + 9$

Step 2

Simplify $4 (v - 1) + 9$ .

Simplify each term.

Apply the distributive property.

$4 v + 6 = 4 v + 4 \cdot - 1 + 9$

Multiply $4$ by $- 1$ .

$4 v + 6 = 4 v - 4 + 9$

Add $- 4$ and $9$ .

$4 v + 6 = 4 v + 5$

Step 3

Move all terms containing $v$ to the left side of the equation.

Subtract $4 v$ from both sides of the equation.

$4 v + 6 - 4 v = 5$

Combine the opposite terms in $4 v + 6 - 4 v$ .

Subtract $4 v$ from $4 v$ .

$0 + 6 = 5$

Add $0$ and $6$ .

$6 = 5$

Step 4

Since $6 \neq 5$ , there are no solutions.

No solution