Solve for v h=vt-16t^2

$h = v t - 16 t^{2}$

Step 1

Rewrite the equation as $v t - 16 t^{2} = h$ .

$v t - 16 t^{2} = h$

Step 2

Add $16 t^{2}$ to both sides of the equation.

$v t = h + 16 t^{2}$

Step 3

Divide each term in $v t = h + 16 t^{2}$ by $t$ and simplify.

Divide each term in $v t = h + 16 t^{2}$ by $t$ .

$\frac{v t}{t} = \frac{h}{t} + \frac{16 t^{2}}{t}$

Simplify the left side.

Cancel the common factor of $t$ .

Cancel the common factor.

$\frac{v t}{t} = \frac{h}{t} + \frac{16 t^{2}}{t}$

Divide $v$ by $1$ .

$v = \frac{h}{t} + \frac{16 t^{2}}{t}$

Simplify the right side.

Cancel the common factor of $t^{2}$ and $t$ .

Factor $t$ out of $16 t^{2}$ .

$v = \frac{h}{t} + \frac{t (16 t)}{t}$

Cancel the common factors.

Raise $t$ to the power of $1$ .

$v = \frac{h}{t} + \frac{t (16 t)}{t^{1}}$

Factor $t$ out of $t^{1}$ .

$v = \frac{h}{t} + \frac{t (16 t)}{t \cdot 1}$

Cancel the common factor.

$v = \frac{h}{t} + \frac{t (16 t)}{t \cdot 1}$

Rewrite the expression.

$v = \frac{h}{t} + \frac{16 t}{1}$

Divide $16 t$ by $1$ .

$v = \frac{h}{t} + 16 t$