Solve for v v+1>v-6

$v + 1 > v - 6$

Step 1

Move all terms containing $v$ to the left side of the inequality.

Subtract $v$ from both sides of the inequality.

$v + 1 - v > - 6$

Combine the opposite terms in $v + 1 - v$ .

Subtract $v$ from $v$ .

$0 + 1 > - 6$

Add $0$ and $1$ .

$1 > - 6$

Step 2

Since $1 > - 6$ , the inequality will always be true for any value of $v$ .

All real numbers

Step 3

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$