Solve for v v^2=17v

$v^{2} = 17 v$

Subtract $17 v$ from both sides of the equation.

$v^{2} - 17 v = 0$

Factor $v$ out of $v^{2} - 17 v$ .

Factor $v$ out of $v^{2}$ .

$v \cdot v - 17 v = 0$

Factor $v$ out of $- 17 v$ .

$v \cdot v + v \cdot - 17 = 0$

Factor $v$ out of $v \cdot v + v \cdot - 17$ .

$v (v - 17) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$v = 0$

$v - 17 = 0$

Set $v$ equal to $0$ .

$v = 0$

Set $v - 17$ equal to $0$ and solve for $v$ .

Set $v - 17$ equal to $0$ .

$v - 17 = 0$

Add $17$ to both sides of the equation.

$v = 17$

The final solution is all the values that make $v (v - 17) = 0$ true.

$v = 0, 17$