Solve for v v^2-25=0

$v^{2} - 25 = 0$

Add $25$ to both sides of the equation.

$v^{2} = 25$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$v = \pm \sqrt{25}$

Simplify $\pm \sqrt{25}$ .

Rewrite $25$ as $5^{2}$ .

$v = \pm \sqrt{5^{2}}$

Pull terms out from under the radical, assuming positive real numbers.

$v = \pm 5$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$v = 5$

Next, use the negative value of the $\pm$ to find the second solution.

$v = - 5$

The complete solution is the result of both the positive and negative portions of the solution.

$v = 5, - 5$