Solve for v v^2+2v-8=0

$v^{2} + 2 v - 8 = 0$

Step 1

Factor $v^{2} + 2 v - 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 8$ and whose sum is $2$ .

$- 2, 4$

Write the factored form using these integers.

$(v - 2) (v + 4) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$v - 2 = 0$

$v + 4 = 0$

Step 3

Set $v - 2$ equal to $0$ and solve for $v$ .

Set $v - 2$ equal to $0$ .

$v - 2 = 0$

Add $2$ to both sides of the equation.

$v = 2$

Step 4

Set $v + 4$ equal to $0$ and solve for $v$ .

Set $v + 4$ equal to $0$ .

$v + 4 = 0$

Subtract $4$ from both sides of the equation.

$v = - 4$

Step 5

The final solution is all the values that make $(v - 2) (v + 4) = 0$ true.

$v = 2, - 4$

Solve for v v^2+2v-8=0

Related Questions

Support LCMGCF.com by disabling your adblocker.