Solve for v v^2+9v+20=0

$v^{2} + 9 v + 20 = 0$

Factor $v^{2} + 9 v + 20$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $20$ and whose sum is $9$ .

$4, 5$

Write the factored form using these integers.

$(v + 4) (v + 5) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$v + 4 = 0$

$v + 5 = 0$

Set $v + 4$ equal to $0$ and solve for $v$ .

Set $v + 4$ equal to $0$ .

$v + 4 = 0$

Subtract $4$ from both sides of the equation.

$v = - 4$

Set $v + 5$ equal to $0$ and solve for $v$ .

Set $v + 5$ equal to $0$ .

$v + 5 = 0$

Subtract $5$ from both sides of the equation.

$v = - 5$

The final solution is all the values that make $(v + 4) (v + 5) = 0$ true.

$v = - 4, - 5$

Solve for v v^2+9v+20=0

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