Solve for v v+3=2(v-7)

$v + 3 = 2 (v - 7)$

Step 1

Simplify $2 (v - 7)$ .

Rewrite.

$v + 3 = 0 + 0 + 2 (v - 7)$

Simplify by adding zeros.

$v + 3 = 2 (v - 7)$

Apply the distributive property.

$v + 3 = 2 v + 2 \cdot - 7$

Multiply $2$ by $- 7$ .

$v + 3 = 2 v - 14$

Step 2

Move all terms containing $v$ to the left side of the equation.

Subtract $2 v$ from both sides of the equation.

$v + 3 - 2 v = - 14$

Subtract $2 v$ from $v$ .

$- v + 3 = - 14$

Step 3

Move all terms not containing $v$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- v = - 14 - 3$

Subtract $3$ from $- 14$ .

$- v = - 17$

Step 4

Divide each term in $- v = - 17$ by $- 1$ and simplify.

Divide each term in $- v = - 17$ by $- 1$ .

$\frac{- v}{- 1} = \frac{- 17}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{v}{1} = \frac{- 17}{- 1}$

Divide $v$ by $1$ .

$v = \frac{- 17}{- 1}$

Simplify the right side.

Divide $- 17$ by $- 1$ .

$v = 17$