Solve for w 2(w+2)+w=3(w-1)+6

$2 (w + 2) + w = 3 (w - 1) + 6$

Simplify $2 (w + 2) + w$ .

Simplify each term.

Apply the distributive property.

$2 w + 2 \cdot 2 + w = 3 (w - 1) + 6$

Multiply $2$ by $2$ .

$2 w + 4 + w = 3 (w - 1) + 6$

Add $2 w$ and $w$ .

$3 w + 4 = 3 (w - 1) + 6$

Simplify $3 (w - 1) + 6$ .

Simplify each term.

Apply the distributive property.

$3 w + 4 = 3 w + 3 \cdot - 1 + 6$

Multiply $3$ by $- 1$ .

$3 w + 4 = 3 w - 3 + 6$

Add $- 3$ and $6$ .

$3 w + 4 = 3 w + 3$

Move all terms containing $w$ to the left side of the equation.

Subtract $3 w$ from both sides of the equation.

$3 w + 4 - 3 w = 3$

Combine the opposite terms in $3 w + 4 - 3 w$ .

Subtract $3 w$ from $3 w$ .

$0 + 4 = 3$

Add $0$ and $4$ .

$4 = 3$

Since $4 \neq 3$ , there are no solutions.

No solution