Solve for w 3(w+2)+w=4(w-1)+9

$3 (w + 2) + w = 4 (w - 1) + 9$

Step 1

Simplify $3 (w + 2) + w$ .

Simplify each term.

Apply the distributive property.

$3 w + 3 \cdot 2 + w = 4 (w - 1) + 9$

Multiply $3$ by $2$ .

$3 w + 6 + w = 4 (w - 1) + 9$

Add $3 w$ and $w$ .

$4 w + 6 = 4 (w - 1) + 9$

Step 2

Simplify $4 (w - 1) + 9$ .

Simplify each term.

Apply the distributive property.

$4 w + 6 = 4 w + 4 \cdot - 1 + 9$

Multiply $4$ by $- 1$ .

$4 w + 6 = 4 w - 4 + 9$

Add $- 4$ and $9$ .

$4 w + 6 = 4 w + 5$

Step 3

Move all terms containing $w$ to the left side of the equation.

Subtract $4 w$ from both sides of the equation.

$4 w + 6 - 4 w = 5$

Combine the opposite terms in $4 w + 6 - 4 w$ .

Subtract $4 w$ from $4 w$ .

$0 + 6 = 5$

Add $0$ and $6$ .

$6 = 5$

Step 4

Since $6 \neq 5$ , there are no solutions.

No solution