Solve for w 3(w+3)+w=2(W-1)+3

$3 (w + 3) + w = 2 (W - 1) + 3$

Step 1

Simplify $3 (w + 3) + w$ .

Simplify each term.

Apply the distributive property.

$3 w + 3 \cdot 3 + w = 2 (W - 1) + 3$

Multiply $3$ by $3$ .

$3 w + 9 + w = 2 (W - 1) + 3$

Add $3 w$ and $w$ .

$4 w + 9 = 2 (W - 1) + 3$

Step 2

Simplify $2 (W - 1) + 3$ .

Simplify each term.

Apply the distributive property.

$4 w + 9 = 2 W + 2 \cdot - 1 + 3$

Multiply $2$ by $- 1$ .

$4 w + 9 = 2 W - 2 + 3$

Add $- 2$ and $3$ .

$4 w + 9 = 2 W + 1$

Step 3

Move all terms not containing $w$ to the right side of the equation.

Subtract $9$ from both sides of the equation.

$4 w = 2 W + 1 - 9$

Subtract $9$ from $1$ .

$4 w = 2 W - 8$

Step 4

Divide each term in $4 w = 2 W - 8$ by $4$ and simplify.

Divide each term in $4 w = 2 W - 8$ by $4$ .

$\frac{4 w}{4} = \frac{2 W}{4} + \frac{- 8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 w}{4} = \frac{2 W}{4} + \frac{- 8}{4}$

Divide $w$ by $1$ .

$w = \frac{2 W}{4} + \frac{- 8}{4}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2 W$ .

$w = \frac{2 (W)}{4} + \frac{- 8}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$w = \frac{2 W}{2 \cdot 2} + \frac{- 8}{4}$

Cancel the common factor.

$w = \frac{2 W}{2 \cdot 2} + \frac{- 8}{4}$

Rewrite the expression.

$w = \frac{W}{2} + \frac{- 8}{4}$

Divide $- 8$ by $4$ .

$w = \frac{W}{2} - 2$

Solve for w 3(w+3)+w=2(W-1)+3

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