Solve for w 4(w+3)=w-15

$4 (w + 3) = w - 15$

Step 1

Simplify $4 (w + 3)$ .

Rewrite.

$0 + 0 + 4 (w + 3) = w - 15$

Simplify by adding zeros.

$4 (w + 3) = w - 15$

Apply the distributive property.

$4 w + 4 \cdot 3 = w - 15$

Multiply $4$ by $3$ .

$4 w + 12 = w - 15$

Step 2

Move all terms containing $w$ to the left side of the equation.

Subtract $w$ from both sides of the equation.

$4 w + 12 - w = - 15$

Subtract $w$ from $4 w$ .

$3 w + 12 = - 15$

Step 3

Move all terms not containing $w$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$3 w = - 15 - 12$

Subtract $12$ from $- 15$ .

$3 w = - 27$

Step 4

Divide each term in $3 w = - 27$ by $3$ and simplify.

Divide each term in $3 w = - 27$ by $3$ .

$\frac{3 w}{3} = \frac{- 27}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 w}{3} = \frac{- 27}{3}$

Divide $w$ by $1$ .

$w = \frac{- 27}{3}$

Simplify the right side.

Divide $- 27$ by $3$ .

$w = - 9$