Solve for w 6w+5>2(3w+3)

$6 w + 5 > 2 (3 w + 3)$

Step 1

Simplify $2 (3 w + 3)$ .

Rewrite.

$6 w + 5 > 0 + 0 + 2 (3 w + 3)$

Simplify by adding zeros.

$6 w + 5 > 2 (3 w + 3)$

Apply the distributive property.

$6 w + 5 > 2 (3 w) + 2 \cdot 3$

Multiply.

Multiply $3$ by $2$ .

$6 w + 5 > 6 w + 2 \cdot 3$

Multiply $2$ by $3$ .

$6 w + 5 > 6 w + 6$

Step 2

Move all terms containing $w$ to the left side of the inequality.

Subtract $6 w$ from both sides of the inequality.

$6 w + 5 - 6 w > 6$

Combine the opposite terms in $6 w + 5 - 6 w$ .

Subtract $6 w$ from $6 w$ .

$0 + 5 > 6$

Add $0$ and $5$ .

$5 > 6$

Step 3

Since $5 < 6$ , there are no solutions.

No solution