Solve for x 0=-2(x-(3x+1))

$0 = - 2 (x - (3 x + 1))$

Step 1

Rewrite the equation as $- 2 (x - (3 x + 1)) = 0$ .

$- 2 (x - (3 x + 1)) = 0$

Step 2

Simplify.

Apply the distributive property.

$- 2 (x - (3 x) - 1 \cdot 1) = 0$

Multiply $3$ by $- 1$ .

$- 2 (x - 3 x - 1 \cdot 1) = 0$

Multiply $- 1$ by $1$ .

$- 2 (x - 3 x - 1) = 0$

Subtract $3 x$ from $x$ .

$- 2 (- 2 x - 1) = 0$

Step 3

Divide each term in $- 2 (- 2 x - 1) = 0$ by $- 2$ and simplify.

Divide each term in $- 2 (- 2 x - 1) = 0$ by $- 2$ .

$\frac{- 2 (- 2 x - 1)}{- 2} = \frac{0}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 (- 2 x - 1)}{- 2} = \frac{0}{- 2}$

Divide $- 2 x - 1$ by $1$ .

$- 2 x - 1 = \frac{0}{- 2}$

Simplify the right side.

Divide $0$ by $- 2$ .

$- 2 x - 1 = 0$

Step 4

Add $1$ to both sides of the equation.

$- 2 x = 1$

Step 5

Divide each term in $- 2 x = 1$ by $- 2$ and simplify.

Divide each term in $- 2 x = 1$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{1}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{1}{- 2}$

Divide $x$ by $1$ .

$x = \frac{1}{- 2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{1}{2}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{2}$

Decimal Form:

$x = - 0.5$

Solve for x 0=-2(x-(3x+1))

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