Solve for x 1/10(x+50)=-3x-13+4x

$\frac{1}{10} (x + 50) = - 3 x - 13 + 4 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 3 x - 13 + 4 x = \frac{1}{10} \cdot (x + 50)$

Add $- 3 x$ and $4 x$ .

$x - 13 = \frac{1}{10} \cdot (x + 50)$

Simplify $\frac{1}{10} \cdot (x + 50)$ .

Apply the distributive property.

$x - 13 = \frac{1}{10} x + \frac{1}{10} \cdot 50$

Combine $\frac{1}{10}$ and $x$ .

$x - 13 = \frac{x}{10} + \frac{1}{10} \cdot 50$

Cancel the common factor of $10$ .

Factor $10$ out of $50$ .

$x - 13 = \frac{x}{10} + \frac{1}{10} \cdot (10 (5))$

Cancel the common factor.

$x - 13 = \frac{x}{10} + \frac{1}{10} \cdot (10 \cdot 5)$

Rewrite the expression.

$x - 13 = \frac{x}{10} + 5$

Move all terms containing $x$ to the left side of the equation.

Subtract $\frac{x}{10}$ from both sides of the equation.

$x - 13 - \frac{x}{10} = 5$

To write $x$ as a fraction with a common denominator, multiply by $\frac{10}{10}$ .

$x \cdot \frac{10}{10} - \frac{x}{10} - 13 = 5$

Combine $x$ and $\frac{10}{10}$ .

$\frac{x \cdot 10}{10} - \frac{x}{10} - 13 = 5$

Combine the numerators over the common denominator.

$\frac{x \cdot 10 - x}{10} - 13 = 5$

Subtract $x$ from $x \cdot 10$ .

Reorder $x$ and $10$ .

$\frac{10 \cdot x - x}{10} - 13 = 5$

Subtract $x$ from $10 \cdot x$ .

$\frac{9 \cdot x}{10} - 13 = 5$

$\frac{9 x}{10} - 13 = 5$

Move all terms not containing $x$ to the right side of the equation.

Add $13$ to both sides of the equation.

$\frac{9 x}{10} = 5 + 13$

Add $5$ and $13$ .

$\frac{9 x}{10} = 18$

Multiply both sides of the equation by $\frac{10}{9}$ .

$\frac{10}{9} \cdot \frac{9 x}{10} = \frac{10}{9} \cdot 18$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{10}{9} \cdot \frac{9 x}{10}$ .

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10}{9} \cdot \frac{9 x}{10} = \frac{10}{9} \cdot 18$

Rewrite the expression.

$\frac{1}{9} (9 x) = \frac{10}{9} \cdot 18$

Cancel the common factor of $9$ .

Factor $9$ out of $9 x$ .

$\frac{1}{9} (9 (x)) = \frac{10}{9} \cdot 18$

Cancel the common factor.

$\frac{1}{9} (9 x) = \frac{10}{9} \cdot 18$

Rewrite the expression.

$x = \frac{10}{9} \cdot 18$

Simplify the right side.

Simplify $\frac{10}{9} \cdot 18$ .

Cancel the common factor of $9$ .

Factor $9$ out of $18$ .

$x = \frac{10}{9} \cdot (9 (2))$

Cancel the common factor.

$x = \frac{10}{9} \cdot (9 \cdot 2)$

Rewrite the expression.

$x = 10 \cdot 2$

Multiply $10$ by $2$ .

$x = 20$

Solve for x 1/10(x+50)=-3x-13+4x

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