Solve for x 1-2(1+3x-2(x+2)+3x)=-1

$1 - 2 (1 + 3 x - 2 (x + 2) + 3 x) = - 1$

Simplify $1 - 2 (1 + 3 x - 2 (x + 2) + 3 x)$ .

Simplify each term.

Apply the distributive property.

$1 - 2 (1 + 3 x - 2 x - 2 \cdot 2 + 3 x) = - 1$

Multiply $- 2$ by $2$ .

$1 - 2 (1 + 3 x - 2 x - 4 + 3 x) = - 1$

Subtract $4$ from $1$ .

$1 - 2 (3 x - 2 x - 3 + 3 x) = - 1$

Subtract $2 x$ from $3 x$ .

$1 - 2 (x - 3 + 3 x) = - 1$

Add $x$ and $3 x$ .

$1 - 2 (4 x - 3) = - 1$

Apply the distributive property.

$1 - 2 (4 x) - 2 \cdot - 3 = - 1$

Multiply $4$ by $- 2$ .

$1 - 8 x - 2 \cdot - 3 = - 1$

Multiply $- 2$ by $- 3$ .

$1 - 8 x + 6 = - 1$

Add $1$ and $6$ .

$- 8 x + 7 = - 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- 8 x = - 1 - 7$

Subtract $7$ from $- 1$ .

$- 8 x = - 8$

Divide each term in $- 8 x = - 8$ by $- 8$ and simplify.

Divide each term in $- 8 x = - 8$ by $- 8$ .

$\frac{- 8 x}{- 8} = \frac{- 8}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 x}{- 8} = \frac{- 8}{- 8}$

Divide $x$ by $1$ .

$x = \frac{- 8}{- 8}$

Simplify the right side.

Divide $- 8$ by $- 8$ .

$x = 1$