Solve for x (1/2)^(7x+1)=-9

${(\frac{1}{2})}^{7 x + 1} = - 9$

Step 1

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln ({(\frac{1}{2})}^{7 x + 1}) = \ln (- 9)$

Step 2

The equation cannot be solved because $\ln (- 9)$ is undefined.

Undefined

Step 3

There is no solution for ${(\frac{1}{2})}^{7 x + 1} = - 9$

No solution

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