Solve for x 1+2x-x=x-5+x

$1 + 2 x - x = x - 5 + x$

Subtract $x$ from $2 x$ .

$1 + x = x - 5 + x$

Add $x$ and $x$ .

$1 + x = 2 x - 5$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$1 + x - 2 x = - 5$

Subtract $2 x$ from $x$ .

$1 - x = - 5$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$- x = - 5 - 1$

Subtract $1$ from $- 5$ .

$- x = - 6$

Divide each term in $- x = - 6$ by $- 1$ and simplify.

Divide each term in $- x = - 6$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 6}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 6}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 6}{- 1}$

Simplify the right side.

Divide $- 6$ by $- 1$ .

$x = 6$