Solve for x 1/3(2x+3)=3

$\frac{1}{3} (2 x + 3) = 3$

Step 1

Multiply both sides of the equation by $3$ .

$3 (\frac{1}{3} \cdot (2 x + 3)) = 3 \cdot 3$

Step 2

Simplify both sides of the equation.

Simplify the left side.

Simplify $3 (\frac{1}{3} \cdot (2 x + 3))$ .

Apply the distributive property.

$3 (\frac{1}{3} (2 x) + \frac{1}{3} \cdot 3) = 3 \cdot 3$

Multiply $\frac{1}{3} (2 x)$ .

Combine $2$ and $\frac{1}{3}$ .

$3 (\frac{2}{3} x + \frac{1}{3} \cdot 3) = 3 \cdot 3$

Combine $\frac{2}{3}$ and $x$ .

$3 (\frac{2 x}{3} + \frac{1}{3} \cdot 3) = 3 \cdot 3$

Cancel the common factor of $3$ .

Cancel the common factor.

$3 (\frac{2 x}{3} + \frac{1}{3} \cdot 3) = 3 \cdot 3$

Rewrite the expression.

$3 (\frac{2 x}{3} + 1) = 3 \cdot 3$

Apply the distributive property.

$3 \frac{2 x}{3} + 3 \cdot 1 = 3 \cdot 3$

Cancel the common factor of $3$ .

Cancel the common factor.

$3 \frac{2 x}{3} + 3 \cdot 1 = 3 \cdot 3$

Rewrite the expression.

$2 x + 3 \cdot 1 = 3 \cdot 3$

Multiply $3$ by $1$ .

$2 x + 3 = 3 \cdot 3$

Simplify the right side.

Multiply $3$ by $3$ .

$2 x + 3 = 9$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$2 x = 9 - 3$

Subtract $3$ from $9$ .

$2 x = 6$

Step 4

Divide each term in $2 x = 6$ by $2$ and simplify.

Divide each term in $2 x = 6$ by $2$ .

$\frac{2 x}{2} = \frac{6}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{6}{2}$

Divide $x$ by $1$ .

$x = \frac{6}{2}$

Simplify the right side.

Divide $6$ by $2$ .

$x = 3$

Solve for x 1/3(2x+3)=3

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