Solve for x 1-3/8x=0

$1 - \frac{3}{8} x = 0$

Step 1

Simplify each term.

Combine $x$ and $\frac{3}{8}$ .

$1 - \frac{x \cdot 3}{8} = 0$

Move $3$ to the left of $x$ .

$1 - \frac{3 x}{8} = 0$

Step 2

Subtract $1$ from both sides of the equation.

$- \frac{3 x}{8} = - 1$

Step 3

Multiply both sides of the equation by $- \frac{8}{3}$ .

$- \frac{8}{3} (- \frac{3 x}{8}) = - \frac{8}{3} \cdot - 1$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{8}{3} (- \frac{3 x}{8})$ .

Cancel the common factor of $8$ .

Move the leading negative in $- \frac{8}{3}$ into the numerator.

$\frac{- 8}{3} (- \frac{3 x}{8}) = - \frac{8}{3} \cdot - 1$

Move the leading negative in $- \frac{3 x}{8}$ into the numerator.

$\frac{- 8}{3} \cdot \frac{- 3 x}{8} = - \frac{8}{3} \cdot - 1$

Factor $8$ out of $- 8$ .

$\frac{8 (- 1)}{3} \cdot \frac{- 3 x}{8} = - \frac{8}{3} \cdot - 1$

Cancel the common factor.

$\frac{8 \cdot - 1}{3} \cdot \frac{- 3 x}{8} = - \frac{8}{3} \cdot - 1$

Rewrite the expression.

$\frac{- 1}{3} (- 3 x) = - \frac{8}{3} \cdot - 1$

Cancel the common factor of $3$ .

Factor $3$ out of $- 3 x$ .

$\frac{- 1}{3} (3 (- x)) = - \frac{8}{3} \cdot - 1$

Cancel the common factor.

$\frac{- 1}{3} (3 (- x)) = - \frac{8}{3} \cdot - 1$

Rewrite the expression.

$- - x = - \frac{8}{3} \cdot - 1$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{8}{3} \cdot - 1$

Multiply $x$ by $1$ .

$x = - \frac{8}{3} \cdot - 1$

Simplify the right side.

Multiply $- \frac{8}{3} \cdot - 1$ .

Multiply $- 1$ by $- 1$ .

$x = 1 (\frac{8}{3})$

Multiply $\frac{8}{3}$ by $1$ .

$x = \frac{8}{3}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{8}{3}$

Decimal Form:

$x = 2.\overline{6}$

Mixed Number Form:

$x = 2 \frac{2}{3}$

Solve for x 1-3/8x=0

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