Solve for x 1/3(9-6x)=5-2x

$\frac{1}{3} (9 - 6 x) = 5 - 2 x$

Step 1

Simplify $\frac{1}{3} \cdot (9 - 6 x)$ .

Rewrite.

$0 + 0 + \frac{1}{3} \cdot (9 - 6 x) = 5 - 2 x$

Simplify by adding zeros.

$\frac{1}{3} \cdot (9 - 6 x) = 5 - 2 x$

Apply the distributive property.

$\frac{1}{3} \cdot 9 + \frac{1}{3} (- 6 x) = 5 - 2 x$

Cancel the common factor of $3$ .

Factor $3$ out of $9$ .

$\frac{1}{3} \cdot (3 (3)) + \frac{1}{3} (- 6 x) = 5 - 2 x$

Cancel the common factor.

$\frac{1}{3} \cdot (3 \cdot 3) + \frac{1}{3} (- 6 x) = 5 - 2 x$

Rewrite the expression.

$3 + \frac{1}{3} (- 6 x) = 5 - 2 x$

Cancel the common factor of $3$ .

Factor $3$ out of $- 6 x$ .

$3 + \frac{1}{3} (3 (- 2 x)) = 5 - 2 x$

Cancel the common factor.

$3 + \frac{1}{3} (3 (- 2 x)) = 5 - 2 x$

Rewrite the expression.

$3 - 2 x = 5 - 2 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$3 - 2 x + 2 x = 5$

Combine the opposite terms in $3 - 2 x + 2 x$ .

Add $- 2 x$ and $2 x$ .

$3 + 0 = 5$

Add $3$ and $0$ .

$3 = 5$

Step 3

Since $3 \neq 5$ , there are no solutions.

No solution