Solve for x (1/3)^(x+3)=10

${(\frac{1}{3})}^{x + 3} = 10$

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln ({(\frac{1}{3})}^{x + 3}) = \ln (10)$

Expand the left side.

Expand $\ln ({(\frac{1}{3})}^{x + 3})$ by moving $x + 3$ outside the logarithm.

$(x + 3) \ln (\frac{1}{3}) = \ln (10)$

Rewrite $\ln (\frac{1}{3})$ as $\ln (1) - \ln (3)$ .

$(x + 3) (\ln (1) - \ln (3)) = \ln (10)$

The natural logarithm of $1$ is $0$ .

$(x + 3) (0 - \ln (3)) = \ln (10)$

Subtract $\ln (3)$ from $0$ .

$(x + 3) (- \ln (3)) = \ln (10)$

Simplify the left side.

Simplify $(x + 3) (- \ln (3))$ .

Apply the distributive property.

$x (- \ln (3)) + 3 (- \ln (3)) = \ln (10)$

Simplify the expression.

Multiply $- 1$ by $3$ .

$x (- \ln (3)) - 3 \ln (3) = \ln (10)$

Reorder factors in $x (- \ln (3)) - 3 \ln (3)$ .

$- x \ln (3) - 3 \ln (3) = \ln (10)$

Move all the terms containing a logarithm to the left side of the equation.

$- x \ln (3) - 3 \ln (3) - \ln (10) = 0$

Move all terms not containing $x$ to the right side of the equation.

Add $3 \ln (3)$ to both sides of the equation.

$- x \ln (3) - \ln (10) = 3 \ln (3)$

Add $\ln (10)$ to both sides of the equation.

$- x \ln (3) = 3 \ln (3) + \ln (10)$

Divide each term in $- x \ln (3) = 3 \ln (3) + \ln (10)$ by $- 1 \ln (3)$ and simplify.

Divide each term in $- x \ln (3) = 3 \ln (3) + \ln (10)$ by $- 1 \ln (3)$ .

$\frac{- x \ln (3)}{- 1 \ln (3)} = \frac{3 \ln (3)}{- 1 \ln (3)} + \frac{\ln (10)}{- 1 \ln (3)}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x \ln (3)}{\ln (3)} = \frac{3 \ln (3)}{- 1 \ln (3)} + \frac{\ln (10)}{- 1 \ln (3)}$

Cancel the common factor of $\ln (3)$ .

Cancel the common factor.

$\frac{x \ln (3)}{\ln (3)} = \frac{3 \ln (3)}{- 1 \ln (3)} + \frac{\ln (10)}{- 1 \ln (3)}$

Divide $x$ by $1$ .

$x = \frac{3 \ln (3)}{- 1 \ln (3)} + \frac{\ln (10)}{- 1 \ln (3)}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $\ln (3)$ .

Cancel the common factor.

$x = \frac{3 \ln (3)}{- 1 \ln (3)} + \frac{\ln (10)}{- 1 \ln (3)}$

Rewrite the expression.

$x = \frac{3}{- 1} + \frac{\ln (10)}{- 1 \ln (3)}$

Move the negative one from the denominator of $\frac{3}{- 1}$ .

$x = - 1 \cdot 3 + \frac{\ln (10)}{- 1 \ln (3)}$

Multiply $- 1$ by $3$ .

$x = - 3 + \frac{\ln (10)}{- 1 \ln (3)}$

Move the negative in front of the fraction.

$x = - 3 - \frac{\ln (10)}{\ln (3)}$

The result can be shown in multiple forms.

Exact Form:

$x = - 3 - \frac{\ln (10)}{\ln (3)}$

Decimal Form:

$x = - 5.09590327 \dots$

Solve for x (1/3)^(x+3)=10

Related Questions

Support LCMGCF.com by disabling your adblocker.