Solve for x 1+4x=13+x

$1 + 4 x = 13 + x$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$1 + 4 x - x = 13$

Subtract $x$ from $4 x$ .

$1 + 3 x = 13$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$3 x = 13 - 1$

Subtract $1$ from $13$ .

$3 x = 12$

Divide each term in $3 x = 12$ by $3$ and simplify.

Divide each term in $3 x = 12$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$x = 4$