Solve for x 1/5(10x-20)=x-3

$\frac{1}{5} (10 x - 20) = x - 3$

Step 1

Simplify $\frac{1}{5} \cdot (10 x - 20)$ .

Rewrite.

$0 + 0 + \frac{1}{5} \cdot (10 x - 20) = x - 3$

Simplify by adding zeros.

$\frac{1}{5} \cdot (10 x - 20) = x - 3$

Apply the distributive property.

$\frac{1}{5} (10 x) + \frac{1}{5} \cdot - 20 = x - 3$

Cancel the common factor of $5$ .

Factor $5$ out of $10 x$ .

$\frac{1}{5} (5 (2 x)) + \frac{1}{5} \cdot - 20 = x - 3$

Cancel the common factor.

$\frac{1}{5} (5 (2 x)) + \frac{1}{5} \cdot - 20 = x - 3$

Rewrite the expression.

$2 x + \frac{1}{5} \cdot - 20 = x - 3$

Cancel the common factor of $5$ .

Factor $5$ out of $- 20$ .

$2 x + \frac{1}{5} \cdot (5 (- 4)) = x - 3$

Cancel the common factor.

$2 x + \frac{1}{5} \cdot (5 \cdot - 4) = x - 3$

Rewrite the expression.

$2 x - 4 = x - 3$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$2 x - 4 - x = - 3$

Subtract $x$ from $2 x$ .

$x - 4 = - 3$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$x = - 3 + 4$

Add $- 3$ and $4$ .

$x = 1$