Solve for x 1+8x+9=-20+2x

$1 + 8 x + 9 = - 20 + 2 x$

Step 1

Add $1$ and $9$ .

$8 x + 10 = - 20 + 2 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$8 x + 10 - 2 x = - 20$

Subtract $2 x$ from $8 x$ .

$6 x + 10 = - 20$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$6 x = - 20 - 10$

Subtract $10$ from $- 20$ .

$6 x = - 30$

Step 4

Divide each term in $6 x = - 30$ by $6$ and simplify.

Divide each term in $6 x = - 30$ by $6$ .

$\frac{6 x}{6} = \frac{- 30}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{- 30}{6}$

Divide $x$ by $1$ .

$x = \frac{- 30}{6}$

Simplify the right side.

Divide $- 30$ by $6$ .

$x = - 5$